Write a program that finds the sum of all numbers between 0 and 120 (inclusive) that are multiples of 4 or 5.
BONUS: allow the user to input their own values for all four variables (both ends of the range and the factors to find multiples).
Discussion
Do you remember prime factorisation trees? 36 9 4 3 3 2 2 Using the diagram, you can see that 3 is the largest prime factor of 36. Your job is to create a program that outputs the largest prime factor of 40478. (BONUS: allow the user to input any number they wish while running the program)
My personal solution in Java:
public static void main(String[] args) {
int sum = 0;
for(int i = 0; i <= 120; i++) {
if(i % 4 == 0 || i % 5 == 0) {
System.out.println(i);
sum += i;
}
}
System.out.println("Sum:\t" + sum);
}
BONUS
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int sum = 0, min, max, fact1, fact2;
System.out.print("Enter the low end of the range:\t"); min = scan.nextInt();
System.out.print("Enter the high end of the range:\t"); max = scan.nextInt();
System.out.print("Enter one factor to find multiples of:\t"); fact1 = scan.nextInt();
System.out.print("Enter another factor to find multiples of:\t"); fact2 = scan.nextInt();
for(int i = min; i <= max; i++) {
if(i % fact1 == 0 || i % fact2 == 0) {
System.out.println(i);
sum += i;
}
}
System.out.println("Sum:\t" + sum);
}